| 如何使用asp上传HTML5 单input多文件 |
3uI0xe http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
xsAy8w http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
brJXze http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
y0ko93 http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
j89BnZ http://blog.numino.net/
End if
UvNUCr http://blog.numino.net/
Next
YJtET9 http://blog.numino.net/
It might be worth trying the same approach - ie:
9EPatx http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
AKvD2Y http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
gkDa8C http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
pxWURC http://blog.numino.net/
End if
M7BDKL http://blog.numino.net/
Next
9NB8uj http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
RN0U4u http://blog.numino.net/
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