| 如何使用asp上传HTML5 单input多文件 |
zjQ77w http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
Yb49f7 http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
nfX0oi http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
Te1n3u http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
i2aP28 http://blog.numino.net/
End if
pbnBh8 http://blog.numino.net/
Next
0N56dF http://blog.numino.net/
It might be worth trying the same approach - ie:
1Q0W7g http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
55JCAm http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
XxqxUz http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
CnCTjL http://blog.numino.net/
End if
00KMGn http://blog.numino.net/
Next
GPWZA1 http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
AvG0j7 http://blog.numino.net/
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