| 如何使用asp上传HTML5 单input多文件 |
U4wqxS http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
uhz4Ad http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
Iz0pPe http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
BX8VCM http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
5FUQa9 http://blog.numino.net/
End if
A3cO8E http://blog.numino.net/
Next
Flt83l http://blog.numino.net/
It might be worth trying the same approach - ie:
V44qZW http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
9IvqH8 http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
rR8cEt http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
HfW4Wd http://blog.numino.net/
End if
Agd1IE http://blog.numino.net/
Next
l8iI0P http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
HIzsB6 http://blog.numino.net/
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