| 如何使用asp上传HTML5 单input多文件 |
do82xK http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
r0Rw4L http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
8lBEod http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
l5LpgE http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
r0xOnJ http://blog.numino.net/
End if
hTApZd http://blog.numino.net/
Next
lUzX0r http://blog.numino.net/
It might be worth trying the same approach - ie:
pABhXX http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
0NLAkq http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
Nl84s9 http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
AyfMXS http://blog.numino.net/
End if
in3227 http://blog.numino.net/
Next
bm06zy http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
2kphzv http://blog.numino.net/
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