| 如何使用asp上传HTML5 单input多文件 |
4w8NDY http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
n8ZJfe http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
nKEiR9 http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
b12HEk http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
2xDSIX http://blog.numino.net/
End if
DKWjWz http://blog.numino.net/
Next
Vu39nj http://blog.numino.net/
It might be worth trying the same approach - ie:
7R3pVD http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
J0piWT http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
4kxxT4 http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
8073tu http://blog.numino.net/
End if
gkj5C7 http://blog.numino.net/
Next
yhB744 http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
gF2y4j http://blog.numino.net/
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