| 如何使用asp上传HTML5 单input多文件 |
qo2M1a http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
uVvaw4 http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
1W8M9J http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
p03BqK http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
57hgwb http://blog.numino.net/
End if
7jswQV http://blog.numino.net/
Next
ezJjcj http://blog.numino.net/
It might be worth trying the same approach - ie:
p012sq http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
6dV5kZ http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
Er92iQ http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
E0YC9b http://blog.numino.net/
End if
wETqqv http://blog.numino.net/
Next
M7CFui http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
Qkk2Ls http://blog.numino.net/
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